Question

evaluate integral dx/x²-16​

Answer 1

Answer✍️

$\int \frac{dx}{ {x}^{2} - 16} = \int \frac{dx}{ {x}^{2} - {4}^{2} } = \frac{1}{8} log| \frac{x - 4}{x + 4} | + C$

$formula \: used \\ \int \frac{dx}{ {x}^{2} + {a}^{2} } = \frac{1}{2a} log| \frac{x - a}{x + a} | + C$

hope this will help you.