a floral design on the floor is made up of 16 types which are triangular. the sides of the triangle are being 9 CM, 28 cm and 35 cm. find the cost of polishing the tiles at the rate of 50 per cm sq.
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Answered by
5
first find out the area of the triangle
by heron's formula
s=(9+28+35)/2
s=36
A={36(36-9)(36-28)(36-35)}^1/2
A=6×16
A=96 sq units
now area of design 16×96
the cost will be
50×16×96
that's it by my side
by heron's formula
s=(9+28+35)/2
s=36
A={36(36-9)(36-28)(36-35)}^1/2
A=6×16
A=96 sq units
now area of design 16×96
the cost will be
50×16×96
that's it by my side
Answered by
6
Hello mate =_=
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Solution:
Semi-perimeter of 1 triangular tile
=s
=(9+28+35)/2=72/2=36 cm
Using Heron's formula, Area of 1 triangular tile
=√{s(s−9)(s−28)(s−35)}
=√{36(36−9)(36−28)(36−35)}
=√{36×27×8×1}
=88.2 cm^2 (approx.)
⇒ Area of 16 triangular tiles =16×88.2=1411.2 cm^2.
Polishing of 1 cm^2 of area costs 50 p
Polishing of 1411.2 cm^2 of area would cost =50×1411.2=70560p= Rs 705.60
hope, this will help you.
Thank you______❤
_____________________________❤
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