A flouride of phosphorous in gaseous state diffuses 2.12 times less than N2 under same condition. calculate molecular weight & molecular formula of phosphorous flouride
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Secondary School Chemistry 5+3 pts
A fluoride of phosphorus in gaseous state was found to diffuse 2.12 times more slowly than nitrogen under similar conditions. calculate the molecular mass and molecular formula of the fluoride which contains obe atom of phosphorus per molecule.
Report by Nayanika56 11.11.2017
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kantnitin
KantnitinVirtuoso
According to Graham's law:
Rate 1Rate 2=M2M1−−−√Rate N2Rate of PFx=MPFxMN2−−−−√2.12 rr=MPFx28 g−−−−√MPFx =125.84 g
The molecular mass is 125.84 g
The molecule contains one P atom so 30 g is contributed by P and rest is by Fl. Fl has molecular mass 19 g and P has 30 g.
So the molecule has one P atom and 5 Fl atoms. Molecular formula is PF5.
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