Question

A flow of 10^7 electrons per second in a conducting wire constitues a current of

Answer 1

Explanation:

As we know ,

I= Q/T

Where I is current ,

Q is charge ,

T is time .

in this question T = 1 second .

Q= no of electrons × charge of one electon

= 10 ^7 × 1.6 × 10^ -19

= 1.6× 10^-12 coloumb

as t = 1

I= Q

therefore ,

I = 1.6 × 10^ -12 Ampere .

hope it will help you ...✌✌✌✌

Answer 2

Answer:

1.6×10^-12

Explanation:

I=Q/T

T= 1 second

Q=10^7×1.6×10^-19

=1.6 × (10^7-19)

=1.6 × 10^-12