Question

A flower basket contains 3 white, 4 red and 5 yellow roses.
What is the minimum number of roses that must be drawn f rom the basket so that you
definitely draw a red rose and a yellow rose?

Answer 1

The minimum number of roses that must be drawn from the basket so that you  definitely draw a red rose and a yellow rose is 9.

Explanation:

Given : The number of white roses = 3

The number of red roses = 4

The number of yellow roses = 5

Total roses = 3+4+5=12

To find : The minimum number of roses that must be drawn from the basket so that you  definitely draw a red rose and a yellow rose.

The number of roses other than red and yellow = (white roses)=3

So the minimum number of roses that must be drawn from the basket so that you  definitely draw a red rose and a yellow rose.

=Total roses - No. of roses other than red and yellow .

= 12-3=9

∴The minimum number of roses that must be drawn from the basket so that you  definitely draw a red rose and a yellow rose is 9.

# Learn more :

A flower basket contains 3 white, 4 red and 5 yellow roses.

What is the minimum number of roses that must be drawn f rom the basket so that you

definitely draw a red rose ?

A.9

A.9

B.8

B.8

C.10

C.10

D.5

D.5

https://brainly.in/question/10602635

Answer 2

A flower basket contains,

white roses = 3 ,

red roses = 4 ,

yellow roses = 5,

Total number of roses = 3 + 4 + 5 = 12

Number of total possible outcomes = 12 --(1)

Number of favourable outcomes = 4 + 5 = 9--(2)

$Probability \: to \: draw \: a \: red \: rose \\and \: a \: yellow \:rose = \frac{(2)}{(1)}\\= \frac{9}{12} \\= \frac{3}{4}$

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