what number must be added to each of the numbers 5 ,9, 7 ,12 to get the numbers which are in proportion?
Answers
Let the no. to be added be x. then, the numbers will be 5+x , 9+x , 7+x and 12+x. = 5+x : 9+x :: 7+x : 12+x = (5+x)/(9+x) = (7+x)/(12+x) =(5+x)(12+x) = (9+x)(7+x) ( Do cross multiplication ) =(60+5x+12x+x square) = (63+9x+7x+x square) =(60+17x+x square) = (63+16x+x square) = 60+17x+x square = 63+16x+x square ( x square and x square gets cancelled ) = 60+17x = 63+16x = 17x - 16x = 63 - 60 = x = 3 Substitution The numbers are: 5+x , 9+x , 7+x and 12+x 5+3 , 9+3 , 7+3 , 12+3 8:12::10:15 Product of extremes = Product of means 8*15 = 12*10 120 = 120 . . . 3 should be added to each of the numbers 5 , 9 , 7 and 12 to get the numbers which are in proportion
Answer:
Answer
3 should be added to each other with the 512 to get the numbers which are in proportion