a fluoride of phosphorus in gaseous state was found to diffuse 2.12 times more slowly than nitrogen under similar conditions. calculate the molecular mass and molecular formula of the fluoride which contains obe atom of phosphorus per molecule.
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Answered by
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According to Graham's law:
Rate 1Rate 2=M2M1−−−√Rate N2Rate of PFx=MPFxMN2−−−−√2.12 rr=MPFx28 g−−−−√MPFx =125.84 g
The molecular mass is 125.84 g
The molecule contains one P atom so 30 g is contributed by P and rest is by Fl. Fl has molecular mass 19 g and P has 30 g.
So the molecule has one P atom and 5 Fl atoms. Molecular formula is PF5.
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Rate 1Rate 2=M2M1−−−√Rate N2Rate of PFx=MPFxMN2−−−−√2.12 rr=MPFx28 g−−−−√MPFx =125.84 g
The molecular mass is 125.84 g
The molecule contains one P atom so 30 g is contributed by P and rest is by Fl. Fl has molecular mass 19 g and P has 30 g.
So the molecule has one P atom and 5 Fl atoms. Molecular formula is PF5.
plzz mark this answer as brainliest
Answered by
3
Answer:
PF5
Explanation:
REFER THE ATTACHMENT
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