Question

A flywheel rotating about a fixed axis has kinetic energy of 360 j when it's angular speed is 30 rad/s. The moment of inertia of wheel about an axis of rotation is

Answer 1

I = mrr

moment of inertia is equal to the product of mass and the square of the radius.

we know rotational kinetic energy = 1/2iww.

then given w= 30 rad and k.E = 360j

k.e= 1/2iww

360 = 1/2× i×30×30

i= 360×2÷30×30

I=12÷15

Answer 2

Explanation:

We know that moment of inertia is equal to M R square and kinetic energy is equal to half I want Mega Square from which we were given by Omega is equal to 20 and kinetic energy is equal to 360 J therefore in kinetic energy is equal to half I oMega Square substitute the given data 360 is equal to half into I into 30 into 30 is equal to 360 is equal to half into 900 into I by simplifying all we get the answer as 0.8 kilogram per metre square

hope its help you...