A food packet is released from a helicopter rising steadily at 2m/s. After 2 sec:
(i)what is the velocity of packet?
(ii) how far is it below the helicopter.
g=9.8m/s
Answers
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b= 19.6 m
a= 39.2 m/s
a= 39.2 m/s
Gautam783:
Full ans plz
h = 1/2gt^2 h= 19.6m and for velocity x=u/t ;u=x/t = 39.2 m/s.
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