Question

A football is kicked at an angle of 37 with a velocity of 20m/s find horizontal range

Answer 1

The initial ( projected) velocity of the football [u] = 20 m/s.

The angle of projection $\theta\ = 37^{0}$

We are asked to calculate the horizontal range of the football.

The horizontal range of a projectile is calculated as -

                         Horizontal range R =  $\frac{u^2 sin2\theta}{g}$

                                                          = $\frac{20^2 sin2\times 37}{g}$

                                                          = $\frac{400sin 74}{9.8}\ m$

                                                          = 39.235 m

Hence, the horizontal range of the body is 39.235 m.