Question

a football player kicks a ball at an angle of 30degree with the horizontal with the velocity of 60m/s .The maximum height reached by the ball is

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Answer 1

Explanation:

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Answer 2

Solution

$\implies$ angle of take off = 30°

initial velocity, u = 15 m/sec

a) Maximum height = $\frac{μ²sin²\emptyset}{2\:×\:60}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ = $\frac{60²sin²\emptyset}{120}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ = $\frac{3117.70}{2\:×\:60}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ = $\frac{3117.70}{120}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ = $25.99$ ( approx )

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