Question

the sum of the 4th and 8th term of an Ap is 24,and sum of the 6th and 10th terms is 44,find the first three terms of the AP ​

Answer 1

Answer:

A4=a+3d

A8=a+7d

And

A6=a+5d

A10=a+9d

Then

a+3d+a+7d=24

a+5d+a+9d=44

By solving we get

(1)-- 2a+10d=24

(2)--2a+14d=44

By elimination we want to do that

We get d=5

Sub d value in (1) then

We get a=-13 then do

A1=a=-13

A2=a+d=-13+(5)=-8

A3=a+2d=-13+2(5)=-13+10=-3

Answer 2

Answer:

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