Math, asked by saileahgupta6, 4 months ago

A footpath of uniform width 5m runs round the inside of a rectangular park 38m long and 32m wide. Find the area of the path.(Fig.11.1)​

Answers

Answered by shriya002
15

Answer:

600 m^2

Step-by-step explanation:

area of the park = l x b

                           = 38 x 32

                           =1216

Area of the park without the footpath

                           = l -(2 x 5) b-(2 x 5)

                           = l - 10 x b - 10

                           = 28 x 22

                           = 616

area of the path = area of rectangle 1 - area of rectangle 2

                           = 1216 - 616

                            = 600

Answered by vilashlaxmi12
2

Answer:

600 m²

Step-by-step explanation:

  • 38×32 1216 m²
  • 38×32 1216 m²38-5-5=28m²
  • 38×32 1216 m²38-5-5=28m²32-5-5=22
  • 38×32 1216 m²38-5-5=28m²32-5-5=2228×22=616m²
  • 38×32 1216 m²38-5-5=28m²32-5-5=2228×22=616m²area of path= 1216-616

= 600m²

Similar questions