A footpath of uniform width 5m runs round the inside of a rectangular park 38m long and 32m wide. Find the area of the path.(Fig.11.1)
Answers
Answered by
15
Answer:
600 m^2
Step-by-step explanation:
area of the park = l x b
= 38 x 32
=1216
Area of the park without the footpath
= l -(2 x 5) b-(2 x 5)
= l - 10 x b - 10
= 28 x 22
= 616
area of the path = area of rectangle 1 - area of rectangle 2
= 1216 - 616
= 600
Answered by
2
Answer:
600 m²
Step-by-step explanation:
- 38×32 1216 m²
- 38×32 1216 m²38-5-5=28m²
- 38×32 1216 m²38-5-5=28m²32-5-5=22
- 38×32 1216 m²38-5-5=28m²32-5-5=2228×22=616m²
- 38×32 1216 m²38-5-5=28m²32-5-5=2228×22=616m²area of path= 1216-616
= 600m²
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