Question

a) For an element with atomic number 29

i) Write the electronic configuration.

ii) Write the value of n and l for its electron in its valence shell.
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Answer 1

Answer:

atomic number 29 is Copper

Explanation:

The electronic configuration of copper is 2,8, 18, 1.

It can also be written as 1s2 2s2 2p6 3s2 3p6 3d10 4s1 4p0 or [Ar]3d10 4s1 4p0 .

n shell = 11 electrons

l shell = 8 electrons 

Answer 2

Actually the electronic configuration of the above answer is correct but the value of n and l is wrong.
So value of n,ie, principal quantum no will be 4
And value of l ie azimuthal quantum no will be 0,1,2,3