Question

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculater work (cas 60=1/2​

Answer 1

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Given:-

$\longrightarrow$ Force = 10 N

$\longrightarrow$ mass = 10 kg

$\longrightarrow$ Angle = 60⁰

$\longrightarrow$ displacement = 5 m

$\longrightarrow$ $\sf Cos60⁰ = \dfrac{1}{2}$

To find:-

$\longrightarrow$ Work done

Formula to be used:-

$\longrightarrow$ $\underline{\boxed{\sf work\: done = Force × displacement × CosØ}}$

Solution:-

$\implies$ $\sf Work\:done = 10 × 5 × \dfrac{1}{2}$

$\implies$ $\sf work\: done = 5 × 5$

$\implies$ $\sf work\: done = 25 Joules$

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Answer 2

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