Question

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculater work (cas 60=1/2​

Answer 1

Correct QUESTION :-

• A force of 10N acts on a block of mass 10kg at an angle of 60° displaces it 5m. calculate the work done. (cos 60°=1/2).

Given:-

• Force Applied = 10N
• Mass of Block = 10kg
• Angle made = 60° = 1/2
• Displacement ( s ) = 5m

To Find:-

• Work Done.

Formulae used:-

Work Done = F × s × Cos O

Now,

→ Work Done = F × s × cos 60°

→ Work done = 10 × 5 × 1/2

→ Work done = 25J

Hence, The work done by the force is 25J.

Answer 2

Given,

• F = 10N
• S = 5m

To Find,

• Work done

Solution,

The Work Done = S × Force × cos∅

→ The Work Done = 5m × 10N × cos(60)

→ The Work done = 50Nm × ½

→ The Work Done = 25Nm

Required Answer,

The Work Done = 25Nm