a force 10N acts on a body of mass 2kg for 3s initially AR rest calculate the velocity acquired by the body and change in momentum of the body
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Force = mass× acceleration
F =10 N
mass = 2 kg
a = F/m = 10/2 = 5 m/s²
i)now, u = 0
t = 3 sec
v = u + at = 0 + 3×5 = 15 m/s
ii) initial momentum = mu = 2×0 =0
final momentum = mv = 2×15 = 30 kg m/s
change in momentum = final momentum - initial momentum
= 30 -0 = 30 kg m/s
F =10 N
mass = 2 kg
a = F/m = 10/2 = 5 m/s²
i)now, u = 0
t = 3 sec
v = u + at = 0 + 3×5 = 15 m/s
ii) initial momentum = mu = 2×0 =0
final momentum = mv = 2×15 = 30 kg m/s
change in momentum = final momentum - initial momentum
= 30 -0 = 30 kg m/s
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