Question

Answer fast Its urgent

Answer 1

Let p/a = x, q/b = y and r/c = 1

       x + y + z = 1

      Squaring on both sides, we get

     (x+y+z)^2 = 1

     x^2 + y^2 + z^2 + 2(xy + yz + xz) = 1  ---- (1)

Given a/p + b/q + c/r = 0  will be their reciprocals = 1/x + 1/y + 1/z = 0.

1/x + 1/y + 1/z = 0

yz + xz + xy = 0    --- (2)

Squaring (2) in (1)

x^2 + y^2 + z^2 + 2(0) = 1

x^2 + y^2 + z^2 = 1.


Hence (p/a)^2 + (q/b)^2 + (r/c)^2 = 1.


Hope this helps!