Question

a force 10n is resolved into the perpendicular components.if the first component make 30 degrees with the force the magnitude of the components are

Answer 1

One component makes 30 degrees with the force vector, thus it must be its cos component.
Therefore Fcos30= 10×root 3/2 = 5root3 N
Fsin30= 10×1/2 = 5 N

Answer 2

5√3N and 5 N are the precise answer.

Given: Force = 10N, angle =30°.

Formula used: Fh=Fcosθ, Fv=Fsinθ.

Solution:

• We will make use of the formulae for calculating the square additives of the pressure to solve this problem. We will alternative the given values, that is, the value of the force and the perspective made with the aid of using the thing of the force regarding the axis.
• The vertical aspect of the force is, Fv=Fsinθ.
• Substitute the given values of the value of the force and perspective made by the primary thing of the force.
• FV=10sin30° ⇒FV=10×1/2⇒FV=5N.
• Therefore, the value of the vertical thing of the force is 5 N.

∴The magnitudes of the additives of the force are 5√3N and 5 N.

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