Question

A force 30 N is applied on a body at an angle of 45° with the horizontal. It does a work of 900 N & 450N horizontal & vertical directions respectively. Calculate the distance travelled in each direction​

Answer 1

Answer:

Explanation:

W= F× cos45 × s

900=30 ×1/√2 ×s

900 = 30/√2 ×s

S= 900×√2 \30

S=30× √2

S=30×1.414

S = 4.242m

Answer 2

We should resolve the force into two components and then use those components to find out the distances.