Question

a force (4 i- 5j + 3 k) is acting at a point (i+ 2j + 3 k) find torque of this force about a point whose position vector is (3i - 2j - 3 k )metres​

Answer 1

Answer: 30√3

Explanation:

       

               r = i+2j+3k-3i+2j+3k

                 = -2i+4j+6k

               F = 4i-5j+3k (given)

         Torque = | r × F |

                      = | 42i+30j-6k|

                      = √(42)^2+(30)^2+(-6)^2

                      = √2700

                      = 30√3