A force =4i+6j+3k acting on a particle produce a displacement of S=2i+3j+5k where f is Express in Newton and 5 is in metre find the work done by the force.
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Answered by
75
Hey user !!!
Here's the answer you are looking for
F = (4i + 6j + 3k)
s = (2i + 3j + 5k)
Work done is the dot product of vector F and vector s.
So, W = F • s
= (4i + 6j + 3k) • (2i + 3j + 5k)
= (4•2) + (6•3) + (3•5)
= 8 + 18 + 15
= 41 Nm = 41J
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
F = (4i + 6j + 3k)
s = (2i + 3j + 5k)
Work done is the dot product of vector F and vector s.
So, W = F • s
= (4i + 6j + 3k) • (2i + 3j + 5k)
= (4•2) + (6•3) + (3•5)
= 8 + 18 + 15
= 41 Nm = 41J
★★ HOPE THAT HELPS ☺️ ★★
Answered by
15
take the for product of two vectors
wokdone = force ×displacement
so with dot product rules mentioned in picture solve it
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