Question

A force =4i+6j+3k acting on a particle produce a displacement of S=2i+3j+5k where f is Express in Newton and 5 is in metre find the work done by the force.

Answer 1

Hey user !!!

Here's the answer you are looking for

F = (4i + 6j + 3k)

s = (2i + 3j + 5k)

Work done is the dot product of vector F and vector s.

So, W = F • s

= (4i + 6j + 3k) • (2i + 3j + 5k)

= (4•2) + (6•3) + (3•5)

= 8 + 18 + 15

= 41 Nm = 41J


★★ HOPE THAT HELPS ☺️ ★★

Answer 2

take the for product of two vectors
wokdone = force ×displacement
so with dot product rules mentioned in picture solve it