If three resistance are connected in series R1=R2=R3=5ohm . Find its equivalent resistance.
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Equivalent resistance is 15
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In a series connection the equivalent resistance is given by the sum of each of the resistances.
Rs=R1 + R2 + R3 +.......+Rn
Here Rs = r1 + r2 + r3
Rs = 5Ω +5Ω + 5Ω
Therefore Rs= 15Ω
Rs=R1 + R2 + R3 +.......+Rn
Here Rs = r1 + r2 + r3
Rs = 5Ω +5Ω + 5Ω
Therefore Rs= 15Ω
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