Question

A Force 5N acts on a body of mass 20kg which was intially at rest.find the distance travalled by the body in 10s​

Answer 1

Answer:

$\longrightarrow$ 12.5 m

Explanation:

As per the provided information in the given question, we have :

• Force applied (F) = 5 N
• Mass (m) = 20 kg
• Initial velocity (u) = 0 m/s
• Time taken (t) = 10 seconds

We are asked to calculate the distance travelled by the body in 10s.

In order to calculate distance travelled, firstly we need to calculate the acceleration.

As we know that,

★ F = ma

• F denotes force
• m denotes mass
• a denotes acceleration

→ 5N = 20 kg × a

→ 5 kg.m/s² ÷ 20 kg = a

→ 0.25 m/s² = a

Henceforth, acceleration of the body is 0.25 m/s².

Now, we have to calculate distance travelled. By using the 2nd equation of motion,

★ s = ut + ½at²

• s denotes distance
• u denotes initial velocity
• a denotes acceleration
• t denotes time

→ s = 0(10) + ½ × 0.25 × (10)²

→ s = ½ × 0.25 × 100

→ s = ½ × 25

→ s = 12.5 m

Therefore, distance travelled by the body in 10s is 12.5 m.