Question

A force acting on a 10 kg mass change its velocity from 6m/s to 3 m/s.
Calculate the work done by the force.​

Answer 1

Explanation:

w= 1/2 mv2

w= 1/2 × 10 ×3×3

w= 1/2 ×90

w = 45unit

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Answer 2

Answer:

135 J

Explanation:

given , mass = 10 kg, initial velocity V1 = 6m/s, final velocity V2 = 3m/s

work done = change in kinetic energy

W = m/2( V2²-V1²)

= 10/2( 3²-6²)

= 5(9-36)

= -5×27

= -135 joule

hence work done against velocity = 135 joule

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