Question

a force acting on a body of mass 7 kg produces an acceleration of 10ms the acceleration that the same force will produce in a body of mass 9 kg will be​

Answer 1

Answer:

Mass=m1=7kg

Mass=m2=9kg

Acceleration=a1=10m/s^2

2

Acceleration=a2=?

Here Force is constant

According to Newtons Law

\boxed{\sf F=ma}

F=ma

ATQ

\begin{gathered}\\ \sf\longmapsto m_1\times a_1=m_2\times a_2\end{gathered}

⟼m

1

×a

1

=m

2

×a

2

\begin{gathered}\\ \sf\longmapsto 7\times 10=9\times a_2\end{gathered}

⟼7×10=9×a

2

\begin{gathered}\\ \sf\longmapsto 70=9a_2\end{gathered}

⟼70=9a

2

\begin{gathered}\\ \sf\longmapsto a_2=\dfrac{70}{9}\end{gathered}

⟼a

2

=

9

70

\begin{gathered}\\ \sf\longmapsto a_2=7.7m/s^2\end{gathered}

⟼a

2

=7.7m/s

2

Answer 2

Answer:

• A force acting on a body of mass 7 kg produces an acceleration of $10\ m/s^{2}$ will be $70\ N$

• If the same force acts on a mass $9\ kg$, the acceleration produced will be $7.7777\ m/s^{2}$

Explanation:

According to Newton's second law of motion,

Force applied (F) will be the product of the mass of the object and its acceleration.

It can be expressed as,

$F = ma$   ...(1)

Where m- the mass of the object and

            a - acceleration

By rearranging the above equation,

$a = \frac{F}{m}$ ...(2)

In the question, it is given that,

$m = 7\ kg$

$a = 10\ m/s^{2}$

Substitute these values into equation(1),

$F = 10\times 5 = 70 N$

If the same force acts on another body,

$m = 9\ kg$    $F = 70N$

Using equation (2),

$a = \frac{70}{9} = 7.7777\ m/s^{2}$