A force acting on a particle of mass 200
g displaces it through 400 cm in 2
seconds. Find the magnitude of the
force if the initial velocity of the particle
is zero.
(A) 0.1 N (B) 0.3 N (C) 0,4 N (D) 0.5 N
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Answer:
C) 0.4 N
Explanation:
Here s= 400cm=4m and u = 0 and t = 2s
s= ut + 1/2×a×t^2
4 = 1/2×a×2^2
4÷2=a
therefore, a= 2m/s^2
hence F= ma
F= 0.2×2
F=0.4
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