A force acting on a particle of mass 200g displaces it through 400 cm in 2s. Find the magnitude of the force if the initial velocity of the particle is zero.
Answers
Answered by
78
Given:
mass=m=200g=0.2kg
distance =s=400cm=4cm
time =t=2sec
u=0m/s
find f??
By second law of motion,
S=ut+1/2at^2
=> 0+1/2×a×4=4
=> a=2m/s^2
By second equation of motion,
F=ma
=> 0.2×2=0.4N
Therefore, Magnitude of force is 0.2N
mass=m=200g=0.2kg
distance =s=400cm=4cm
time =t=2sec
u=0m/s
find f??
By second law of motion,
S=ut+1/2at^2
=> 0+1/2×a×4=4
=> a=2m/s^2
By second equation of motion,
F=ma
=> 0.2×2=0.4N
Therefore, Magnitude of force is 0.2N
Answered by
25
F=mv-mu/t,, putting the values, we get, force =0.04 N
sameer138:
sorry sorry by mistake, this is wrong
ohhhhhhh
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