Question

A force acts for 0.1 s on a body of mass 2-0 kg
initially at rest. The force is then withdrawn and
the body moves with a velocity of 2 m/s. Find the
magnitude of force.
​

Answer 1

t=0 is. m=2kg

u=0. v=2m/s

now,. F=m×a. =m×(v-u)/t

=2×(2-0)/0.1=2×2/1

=4×10=40newtons