Question

A force acts for 0.2 s on a body of mass 2.5 kg initially at rest. The force then ceases to act and the body moves through 4m in the next one second. Calculate the magnitude of force.

Answer 1

Answer:

formula:ma

by frist equation of motion

v=u+at

a=v-u/t

then a=20m/s-2

and by second law of motion

F=ma

F=2.5×20

F=50N

hope it is help you