a force acts for 0.2 sec on an object having mass 1.4 kg initially at rest.The force stops to act but the object moves through 4m in the next 2 sec find the magnitude of the force?
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F=ma
F=m(v-u/t)
F=1.4(v-u)/0.2
F=7(v-u) -eq.1
s=ut +at^2/2
s=0t+2^2a/2
4=a*4/2
a=2 -eq.2
as f=ma
f=1.4*2
=2.8N
F=m(v-u/t)
F=1.4(v-u)/0.2
F=7(v-u) -eq.1
s=ut +at^2/2
s=0t+2^2a/2
4=a*4/2
a=2 -eq.2
as f=ma
f=1.4*2
=2.8N
BhujangaReddy:
answer should be 14N
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