Question

a force acts for 0.2 sec on an object having mass 1.4 kg initially at rest.The force stops to act but the object moves through 4m in the next 2 sec find the magnitude of the force?

Answer 1

F=ma
F=m(v-u/t)
F=1.4(v-u)/0.2
F=7(v-u)  -eq.1
s=ut +at^2/2
s=0t+2^2a/2
4=a*4/2
a=2  -eq.2
as f=ma
f=1.4*2
=2.8N

Answer 2

Explanation:

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