a force acts for 10 s on a stationary body of mass 100 kg after which the force ceases to act . the body moves through a distance of 100 m in the next 5 s calculate the velocity acquired by the body , acceleration produced by the force, the magnitude of force
Answers
Answered by
17
Given initial t = 10s
m = 100kg
d = 100m
Final t = 5s
(a) Acquired velocity
V = d/t
= 100/5=20m/s
(b) acceleration = change in velocity) time
a = (v-u)/t [ t = total time taken ]
Since the body is stationary, u = 0
a = (20-0)/(10+5)=1.33m/s^2
(c) F = ma = 100 x 1.33 = 133 N
m = 100kg
d = 100m
Final t = 5s
(a) Acquired velocity
V = d/t
= 100/5=20m/s
(b) acceleration = change in velocity) time
a = (v-u)/t [ t = total time taken ]
Since the body is stationary, u = 0
a = (20-0)/(10+5)=1.33m/s^2
(c) F = ma = 100 x 1.33 = 133 N
Similar questions