Question

A force acts on 10s on a stationary body of mass 100kg after which the force cease to act. the body moves through a distance pf 100 m in next 5 sec. calculate (i) velocity acquired by body (ii) acceleration produced by force (iii) the magnitude of force​

Answer 1

Answer:

Let initial velocity = u = 0

Using equation of motion, v = u +at = 0+a(10) = 10a

distance in 10 sec = s = vt = 100=10a(5)

a=2m/s

2

∴v=10a=10(2)m/s=20m/s