Physics, asked by alex777, 9 months ago

A force acts on a 30 g particle in such a way that
the position of the particle as a function of time
is given by x = 3t - 4t2 + t, where x is in metres
and t is in seconds. The work done during the first
4 second is :-
(1) 5.28 J
(2) 450 mJ
(3) 490 mJ
(4) 530 mJ​

Answers

Answered by YuiMisaki
16

Hope you got your answer.

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