Question

point s is any point on side QR of triangle PQR prove that PQ+QR+RP>2PS

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

In ΔPQS

Sum of any two sides is greater than the third side.

So, PQ + QS > PS ......(1)

In ΔPSR

Sum of any two sides is greater than the third side.

So, PR + SR > PS ...(2)

Adding equations (1) and (2)

PQ + PR + QS + SR > PS + PS

PQ + PR + QR > 2PS   [ QS + SR = QR]