An aeroplane after landing to the runway with a speed of 36 km/h travels in a straight line for 5 s and comes to rest with an acceleration of -2 m/s square.Calculate the distance travelled by the aeroplane through the runway.
Answers
Answered by
3
Distance travels by plane is 75 meters.
Explanation:
Given
- Initial velocity=Vi = 36km/hr = 10 m/s
- Time taken =t = 5 sec
- Final velocity =Vf= 0
- Acceleration =a= - 2m/s^2
- Find distance = S=??
As we know
2nd equation of motion
S = Vit + 1/2 (at^2)
S = 10×5 + 1/2 (2×5^2)
S = 50 + 1/2 ( 50)
S = 50 + 25
S= 75 meters
- Distance covered by plane is 75 meters.
Hope it helps
Mark me Brainliest
Similar questions