Question

find the area of an isosceles triangle whose equal side is 6cm,6cm and 8cm

Answer 1

Question:

• Find the area of an isosceles triangle whose sides are 6cm, 6cm and 8cm.

To Find:

• Area of the triangle = ?

Solution:

Perimeter of the triangle = Sum of all sides

= (6 + 6 + 8)cm

= 20cm

Semi-perimeter of the triangle = $\dfrac{Perimeter}{2}=\dfrac{20cm}{2}=10cm$

Area of triangle, when all sides are given:

$\left\{\sqrt{s(s-a)(s-b)(s-c)}\right\}sq.\: units$

Note: Here s stands for Semi-perimeter and a, b, c stands for lengths of three sides.

After substituting values, we get:

$=\left\{\sqrt{10(10-6)(10-6)(10-8)}\right\}cm^2$

$=\left\{\sqrt{10\times4\times4\times2}\right\}cm^2$

$=\left\{\sqrt{10\times4\times4\times2}\right\}cm^2$

$=\left\{\sqrt{320}\right\}cm^2$

$=17.88\:cm^2$

Hence, the area of the isosceles triangle is 17.88cm².