Physics, asked by beihnawzi1, 1 year ago

A force acts on a 3g particle in such a way that the position of the particle as a function of time is given by x=3t-4t 2 +t 3 where x is in meters and t is in seconds. The work done during the first 4 sec.

Answers

Answered by Princess45
1
displacement =3(4) - 4(4)(4) + (4)(4)(4)
= 12

force = 3g

work= (3 x 12 ) = 36 erg
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