Question

A force acts on a 5kg object mass changes its velocity from 5m/s square to 2m/s square. Calculate the work done by the force.


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Answer 1

ANSWER:

• The work done by the force = - 52.5 J

GIVEN:

• A force acts on a 5 kg object mass changes its velocity from 5 m/s² to 2 m/s².

TO FIND:

• The work done by the force.

EXPLANATION:

$\boxed{ \bold{ \purple{ \large{K.E = \dfrac{1}{2} mv^2}}}}$

$\textbf{Here work done will be by Kinetic Energy}$

$\sf \dashrightarrow\Delta K.E = K.E_f -K.E_i$

$\sf \dashrightarrow\Delta K.E = \dfrac{1}{2} mv_f^2 - \dfrac{1}{2} mv_i^2$

$\implies \sf m= 5 \ kg$

$\implies \sf v_f = 2 \ ms^{-1}$

$\implies \sf v_i = 5 \ ms^{-1}$

$\sf \dashrightarrow\Delta K.E = \dfrac{1}{2} 5(2)^2 - \dfrac{1}{2} 5(5)^2$

$\sf \dashrightarrow\Delta K.E = \dfrac{1}{2}(5)(4)- \dfrac{1}{2}(5) (25)$

$\sf \dashrightarrow\Delta K.E = (5)(2)- (5) (12.5)$

$\sf \dashrightarrow\Delta K.E = 10 - 62.5$

$\sf \dashrightarrow\Delta K.E = - 52.5\ J$

Hence the work done by the force = - 52.5 J.

Answer 2

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