A force acts on a body of mass 10 kg. If
the velocity of the body changes from 5 m/s to
3 m/s, then what is the work done bey the force ?
Answers
Answered by
1
Answer:
According to the work energy theorem,
For work done W and kinetic energy ke
W=∆ke
W=ke(f)-ke(i)
=Mv(f)^2÷2 - Mv(i)^2÷2
={M(v(f)^2 - v(i)^2)}÷2
={10(3^2 -5^2)}÷2
={10(9–25)}÷2
=(10×-16)÷2
=-80 joules
As the work is negative in value means that the work is done by the body and it is of 80 joules.
Explanation:
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Answered by
0
Answer:
-80 Joules
Explanation:
1/2*10(v^2-u^2)
5(3^2-5^2)
5(9-25)
5*-16
-80 Joules
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