Question

A force acts on a body of mass 5 kg. After 10 sec the force is withdrawn. Now the body travels 100 m in next 10 sec with uniform velocity. Find the force. ​

Answer 1

Explanation:

Using second equation of motion we can find the acceleration

s = ut + 12at2

5 = 0(5) + 12a52

a = 25m/s2

And hence,

F = ma

= 25 × 10

= 4N

Answer 2

Answer:

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Explanation:

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