A force F= 10 N accelerates a box over a displacement 2 m. The floor is rough and exerts a friction force 1 = 2 N. Determine the network done on
the box.
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19 joule
Explanation:
Given
F=10N
S=2m
Friction Force=2N
Work done F×S
10×2=20Joule
Net work done after friction
20-1=19 joule
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