A force f = 10N, large and fixed direction. The shifting point of force shifts along a straight line of 5m in length. The f force forms the angle of the theta toward the displacement direction. It turns out the style of doing business by 25 joules. Large corner of the theta is ....
Answers
Answered by
0
F = 10 N
S = 5 m
W = 25 J
Θ = __?
W = F S cos θ
25 = 10 • 5 • cos θ
½ = cos θ
Θ = 60 °
S = 5 m
W = 25 J
Θ = __?
W = F S cos θ
25 = 10 • 5 • cos θ
½ = cos θ
Θ = 60 °
Answered by
0
We know that,
F = 10 N
S = 5 m
W = 25 J
Theta angle= ?
W = F S cos theta
25 = 10 * 5 * cos theta
25=50 * cos theta
1/2 = cos theta
1/2 cos theta= 60 °
Cos theta= 60 °
Your answer= 60°
Hope it helps you
F = 10 N
S = 5 m
W = 25 J
Theta angle= ?
W = F S cos theta
25 = 10 * 5 * cos theta
25=50 * cos theta
1/2 = cos theta
1/2 cos theta= 60 °
Cos theta= 60 °
Your answer= 60°
Hope it helps you
Similar questions
English,
8 months ago
Math,
8 months ago
Math,
8 months ago
English,
1 year ago
Social Sciences,
1 year ago