Question

A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 is :
(1) 30J
(2) 5J
(3) 25J
(4) 20J

Answer 1

Work done by this force to move the particle from y = 0 to y = 1 is 25 j.

Step by step explanation:

Work done by varying forces:

The work done by variable force acting on a object that undergoes a displacement is equal to the area.

It can be indicated by the following formula.

          $\bold{Work\,done\,by\,variable\,force=\int F.dy}$

                                      $Work\,done= \int ^{y=1}_{y=0} f.dy$

                                                       $\Rightarrow \int^{1}_{0}(20+10y)dy$

                                                       $\Rightarrow [20y+\frac{10}{2}y^{2}]_{0}^{1}$

                                                       $\Rightarrow 20+\frac{10}{2}=25J$

Therefore, work done is 25 j.

Hence, correct option is 3