Question

A force f=3i-2j+4k displace a body from a point a(8,-2,-3) to a point b(-2,0,6) the work done is

Answer 1

Please see the attachment

Answer 2

The work done by the body is equal to 2 joules.

Explanation:

It is given that,

Force acting on a body, $F=3i-2j+4k$

Initial position of the particle, $a=8i-2j-3k$

Final position of the particle, $b=-2i+0j+6k$

Displacement of the particle = final position - initial position

$d=(-2i+0j+6k)-(8i-2j-3k)$

$d=-10i+2j+9k$

Work done by the body is equal to the dot product of force and displacement. It is given by :

$W=Fd$

$W=(3i-2j+4k){\circ} (-10i+2j+9k)$

$W=-30-4+36$

W = 2 J

So, the work done by the body is equal to 2 joules. Hence, this is the required solution.

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Work done

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