a force F=-3i+4j+6k acts on a body and is displaced by 3m along z-axis what is the work done by the force
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Answer:
The work done = 18 J
Explanation:
Since the work done is along z axis only the other i.e x and ycomponets will be 0.
So,
Here
F= 6 N
Work done= Force×displacement = 6×3 J = 18J
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