A force F→
= 3i + 4j newton is applied on a body of mass 2 kg. Calculate the magnitude and
direction of the acceleration in the body.
Answers
Answered by
9
F = 3 i^ + 4j^
| F | = √ 9+16 = √ 25 = 5 Newton
Now ,
a = F / m
= 5/2 = 2.5 m/s^2
Acceleration will be applied in the direction of the force.
Direction of force = 4/3 = tan theta
Therefore,
acceleration will be applied in the direction
tan^-1(4/3).
| F | = √ 9+16 = √ 25 = 5 Newton
Now ,
a = F / m
= 5/2 = 2.5 m/s^2
Acceleration will be applied in the direction of the force.
Direction of force = 4/3 = tan theta
Therefore,
acceleration will be applied in the direction
tan^-1(4/3).
Similar questions