A force f=4i+6j+3k acting on a particle produces a displacement of s=2i+3j+5k where f is expressed in newton and s in meter find the work done by the force
Answers
Answered by
2
work done =scalar product of force and displacement.
here F= 4i +6j+3k.
r=2i+3j+5k.
w=F.r=(4i+6j+3k)(2i+3j+5k)
w=8+18+15=41joule
here F= 4i +6j+3k.
r=2i+3j+5k.
w=F.r=(4i+6j+3k)(2i+3j+5k)
w=8+18+15=41joule
Answered by
0
Use formula w=F.r. ..........
Similar questions