Question

A force F = 5 î+6 ·-4Â acting on a body produces a displacement S = 6 î+5ł. The work done by the
force is 5n units then value of n =​

Answer 1

Given that,

Initial speed of a jeep, u = 0

Time, t = 5.21 s

Distance, d = 110 m

To find,

The acceleration of the jeep.

Solution,

To find the acceleration, in this case, use second equation of kinematics as :

$d=ut+\dfrac{1}{2}at^2$

Put all values, we get :

$d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 110}{(5.21)^2}\\\\a=8.1\ m/s^2$

So, the acceleration of the jeep is $8.1\ m/s^2$

Answer 2

$\huge\underbrace\mathfrak \red{ANSWER }$

Given that,

Initial speed of a jeep, u = 0

Time, t = 5.21 s

Distance, d = 110 m

To find,

The acceleration of the jeep.

Solution,

To find the acceleration, in this case, use second equation of kinematics as :

$d=ut+\dfrac{1}{2}at^2$

Put all values, we get :

$d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 110}{(5.21)^2}\\\\a=8.1\ m/s^2$

So, the acceleration of the jeep is $8.1\ m/s^2$

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