A force f=5i+2j-5k acts on a particle whose position vector is r=i-2j+k. what is the torque
Answers
Answered by
17
Torque = F ✖ R
= (5i+2j-5k)( i-2j+k)
= -10k + 5j -2k + 2i +5j +10i
= 12i + 10j -12 k
Torque acting = 12i + 10j -12 k
= (5i+2j-5k)( i-2j+k)
= -10k + 5j -2k + 2i +5j +10i
= 12i + 10j -12 k
Torque acting = 12i + 10j -12 k
Similar questions